A car covers a certain distance at 45 km/h. If it increases its speed to 60 km/h, it arrives 30 minutes earlier. Find the total distance. MCQ with Answer and Explanation

A car covers a certain distance at 45 km/h. If it increases its speed to 60 km/h, it arrives 30 minutes earlier. Find the total distance.
A. 90 km
B. 120 km
C. 100 km
D. 80 km
Answer: Option A
Solution (By JKSSB Mock Tests)
Time difference = 30 minutes = 0.5 hours. Let distance be d. d / 45 - d / 60 = 0.5 => (4d - 3d) / 180 = 0.5 => d / 180 = 0.5 => d = 90 km.

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Practice More Time Speed and Distance Questions

Question #1
A runner covers a 400-meter track. The winner finishes in 40 seconds, while the runner-up takes 44 seconds. By what distance does the winner beat the runner-up?
A. 38.5 meters
B. 34.2 meters
C. 40.0 meters
D. 36.36 meters

Correct Answer: Option D


Explanation:
Speed of runner-up = 400 / 44 = 100 / 11 m/s. Distance covered by runner-up in 40 seconds = (100 / 11) * 40 = 4000 / 11 = 363.63 meters. Winning margin = 400 - 363.63 = 36.36 meters.

This question belongs to: Maths Time Speed and Distance
Question #2
A passenger train 200 meters long crosses a platform 300 meters long in 20 seconds. What is the speed of the train in km/h?
A. 100 km/h
B. 110 km/h
C. 80 km/h
D. 90 km/h

Correct Answer: Option D


Explanation:
Total distance = 200 + 300 = 500 meters. Speed = 500 / 20 = 25 m/s. Converting to km/h = 25 * (18/5) = 90 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3
A train 100 meters long passes an extension platform 300 meters long in 20 seconds. What is the speed of the train in km/h?
A. 80 km/h
B. 84 km/h
C. 72 km/h
D. 64 km/h

Correct Answer: Option C


Explanation:
Total distance = 100 + 300 = 400 meters. Speed = 400 / 20 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.

This question belongs to: Maths Time Speed and Distance