A car covers a distance of 180 km at a uniform speed. If the speed is increased by 10 km/h, the journey takes 3 hours. Find the initial speed of the car. MCQ with Answer and Explanation

A car covers a distance of 180 km at a uniform speed. If the speed is increased by 10 km/h, the journey takes 3 hours. Find the initial speed of the car.
A. 45 km/h
B. 50 km/h
C. 55 km/h
D. 60 km/h
Answer: Option B
Solution (By JKSSB Mock Tests)
New speed = 180 / 3 = 60 km/h. Since the new speed is 10 km/h faster than the original speed, original speed = 60 - 10 = 50 km/h.

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Practice More Time Speed and Distance Questions

Question #1
A person covers a certain distance at a certain speed. If he reduces his speed by 20%, he takes 15 minutes more to cover the same distance. Find his usual time.
A. 75 minutes
B. 60 minutes
C. 80 minutes
D. 50 minutes

Correct Answer: Option B


Explanation:
New Speed = 0.8 * Usual Speed. Since distance is constant, New Time = Usual Time / 0.8 = 1.25 * Usual Time. Increase in time = 0.25 * Usual Time = 15 minutes. Usual Time = 15 / 0.25 = 60 minutes.

This question belongs to: Maths Time Speed and Distance
Question #2
A cyclist covers 500 meters in 2 minutes. What is his speed in km/h?
A. 15 km/h
B. 12 km/h
C. 18 km/h
D. 16 km/h

Correct Answer: Option A


Explanation:
Time = 2 minutes = 120 seconds. Speed = 500 / 120 = 25/6 m/s. In km/h = (25/6) * (18/5) = 5 * 3 = 15 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3
A car covered a distance of 400 km at a uniform speed. If the uniform speed index is lowered by 10 km/h, the journey takes 2 hours longer. Find the original speed.
A. 55 km/h
B. 60 km/h
C. 50 km/h
D. 45 km/h

Correct Answer: Option C


Explanation:
Let original speed be s. 400 / (s - 10) - 400 / s = 2 => 200 / (s - 10) - 200 / s = 1 => 2000 = s(s - 10). Solving s^2 - 10s - 2000 = 0 yields (s - 50)(s + 40) = 0. Original speed = 50 km/h.

This question belongs to: Maths Time Speed and Distance