A car driver leaves Bangalore at 8:30 AM and expects to reach a place 300 km away at 12:30 PM. At 10:30 AM he finds that he has covered only 40% of the distance. By how much must he increase the speed of the car to reach on scheduled time? MCQ with Answer and Explanation

A car driver leaves Bangalore at 8:30 AM and expects to reach a place 300 km away at 12:30 PM. At 10:30 AM he finds that he has covered only 40% of the distance. By how much must he increase the speed of the car to reach on scheduled time?
A. 20 km/h
B. 35 km/h
C. 25 km/h
D. 30 km/h
Answer: Option D
Solution (By JKSSB Mock Tests)
Total time available = 4 hours. At 10:30 AM (after 2 hours), distance covered = 40% of 300 = 120 km. Remaining distance = 180 km. Remaining time = 12:30 PM - 10:30 AM = 2 hours. Required speed = 180 / 2 = 90 km/h. Original speed = 120 / 2 = 60 km/h. Increase in speed = 90 - 60 = 30 km/h.

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Practice More Time Speed and Distance Questions

Question #1
A train running at 75 km/h overtakes a motor cyclist riding at 15 km/h in the same direction in 15 seconds. Find the absolute length of the train.
A. 300 meters
B. 270 meters
C. 220 meters
D. 250 meters

Correct Answer: Option D


Explanation:
Relative speed = 75 - 15 = 60 km/h = 60 * (5/18) = 50/3 m/s. Length of train = Relative speed * Time = (50/3) * 15 = 250 meters.

This question belongs to: Maths Time Speed and Distance
Question #2
A boat can row 15 km/h in still water. If the river current flows at 3 km/h, find the distance covered by the boat downstream in 20 minutes.
A. 8 km
B. 5 km
C. 7 km
D. 6 km

Correct Answer: Option D


Explanation:
Downstream speed = 15 + 3 = 18 km/h. Time = 20 minutes = 20/60 = 1/3 hour. Distance covered = Speed * Time = 18 * (1/3) = 6 km.

This question belongs to: Maths Time Speed and Distance
Question #3
A train 150 meters long completely passes a station pole sign in 6 seconds flat. Find its speed in km/h.
A. 110 km/h
B. 80 km/h
C. 100 km/h
D. 90 km/h

Correct Answer: Option D


Explanation:
Speed of train = 150 / 6 = 25 m/s. Converting to km/h = 25 * (18/5) = 90 km/h.

This question belongs to: Maths Time Speed and Distance