A car traveling at a uniform speed covers 300 km. If the speed had been 10 km/h more, it would have taken 1 hour less. Find the initial speed. MCQ with Answer and Explanation

A car traveling at a uniform speed covers 300 km. If the speed had been 10 km/h more, it would have taken 1 hour less. Find the initial speed.
A. 45 km/h
B. 50 km/h
C. 60 km/h
D. 55 km/h
Answer: Option B
Solution (By JKSSB Mock Tests)
Let original speed be s. 300 / s - 300 / (s + 10) = 1 => 300(10) = s(s + 10) => 3000 = s(s + 10). Solving s^2 + 10s - 3000 = 0 gives (s - 50)(s + 60) = 0. Since speed is positive, s = 50 km/h.

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Practice More Time Speed and Distance Questions

Question #1
A boat covers 40 km downstream in 4 hours and the same distance upstream in 8 hours. Find the speed of the stream.
A. 2.5 km/h
B. 3.5 km/h
C. 2.0 km/h
D. 3.0 km/h

Correct Answer: Option A


Explanation:
Downstream speed = 40 / 4 = 10 km/h. Upstream speed = 40 / 8 = 5 km/h. Speed of stream = (10 - 5) / 2 = 5 / 2 = 2.5 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
A man can row 8 km/h in still water. If the river current flows at 2 km/h, it takes him 3.2 hours to row to a place and back. How far is the place?
A. 15 km
B. 12 km
C. 10 km
D. 14 km

Correct Answer: Option B


Explanation:
Downstream speed = 8 + 2 = 10 km/h. Upstream speed = 8 - 2 = 6 km/h. Let distance be d. d / 10 + d / 6 = 3.2 => 16d / 60 = 3.2 => 16d = 192 => d = 12 km.

This question belongs to: Maths Time Speed and Distance
Question #3
A car travels the first half of a total distance at speed v1 and the second half at speed v2. What is the expression for the average speed of the car?
A. (v1 + v2) / 2
B. 2 / (v1 + v2)
C. 2v1*v2 / (v1 + v2)
D. v1*v2 / (v1 + v2)

Correct Answer: Option C


Explanation:
When equal distances are traveled at speeds v1 and v2, the average speed is the harmonic mean: 2v1*v2 / (v1 + v2).

This question belongs to: Maths Time Speed and Distance