A cell of emf 2 V and internal resistance 0.5 Ω is connected to a 3.5 Ω resistor. Terminal voltage is MCQ with Answer and Explanation

A cell of emf 2 V and internal resistance 0.5 Ω is connected to a 3.5 Ω resistor. Terminal voltage is
A. 1.75 V
B. 1.5 V
C. 0.25 V
D. 2 V
Answer: Option A
Solution (By JKSSB Mock Tests)
I = E/(R+r) = 2/(3.5+0.5) = 2/4 = 0.5 A. Terminal V = IR = 0.5×3.5 = 1.75 V. Or E - Ir = 2 - 0.5×0.5 = 1.75 V.

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Question #1
A block of mass 5 kg is pushed against a wall with a horizontal force of 50 N. If coefficient of friction is 0.4, the block
A. Moves up
B. Oscillates
C. Falls down
D. Remains at rest

Correct Answer: Option D


Explanation:
Maximum friction = μN = 0.4×50 = 20 N. Weight = 50 N. Friction < weight, so block will fall. Wait, force 50 N horizontal, weight 5×10=50 N. Frictional force upward max 20 N, weight 50 N down, net downward 30 N, so it slides down. So it falls down. Answer A. Let's correct: option A: Falls down. I'll set A.

This question belongs to: Science Physics
Question #2
The number of significant figures in 0.0034060 is
A. 7
B. 6
C. 4
D. 5

Correct Answer: Option D


Explanation:
Leading zeros (before first non-zero digit) are not significant. So 0.0034060: the first non-zero is 3, then 4,0,6 are significant, and the trailing zero after decimal is significant. Thus significant digits are 3,4,0,6,0 — 5 digits. Note: The last zero indicates precision. Answer is 5.

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Question #3
Instrument measuring humidity:
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Correct Answer: Option B


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