A commuter walking at 5/6 of his regular pace reaches his station 10 minutes late. Find his typical time to reach the station. MCQ with Answer and Explanation

A commuter walking at 5/6 of his regular pace reaches his station 10 minutes late. Find his typical time to reach the station.
A. 45 minutes
B. 55 minutes
C. 50 minutes
D. 60 minutes
Answer: Option C
Solution (By JKSSB Mock Tests)
New speed = 5/6 of usual speed => New time = 6/5 of usual time. Difference = 1/5 of usual time = 10 minutes. Typical baseline time = 10 * 5 = 50 minutes.

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Practice More Time Speed and Distance Questions

Question #1
A train 180 meters long running at 72 km/h crosses a modern platform in 20 seconds. Find the length of the platform.
A. 250 meters
B. 200 meters
C. 240 meters
D. 220 meters

Correct Answer: Option D


Explanation:
Speed of train = 72 * (5/18) = 20 m/s. Total distance covered in 20 seconds = 20 * 20 = 400 meters. Length of platform = Total distance - Length of train = 400 - 180 = 220 meters.

This question belongs to: Maths Time Speed and Distance
Question #2
Excluding stoppages, the speed of an inter-city bus is 45 km/h and including stoppages it is 36 km/h. How many minutes does the bus stop per hour?
A. 12 minutes
B. 15 minutes
C. 18 minutes
D. 10 minutes

Correct Answer: Option A


Explanation:
Stoppage time per hour = (45 - 36) / 45 = 9 / 45 = 1/5 hour. In minutes = (1/5) * 60 = 12 minutes.

This question belongs to: Maths Time Speed and Distance
Question #3
A train 160 meters long passes a platform 240 meters long in 20 seconds. Find the speed of the train in km/h.
A. 72 km/h
B. 84 km/h
C. 80 km/h
D. 64 km/h

Correct Answer: Option A


Explanation:
Total distance = 160 + 240 = 400 meters. Speed = 400 / 20 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.

This question belongs to: Maths Time Speed and Distance