A cyclist travels at a speed of 12 km/h for the first 10 km and at a speed of 10 km/h for the next 12 km. Find his average speed for the entire trip. MCQ with Answer and Explanation

A cyclist travels at a speed of 12 km/h for the first 10 km and at a speed of 10 km/h for the next 12 km. Find his average speed for the entire trip.
A. 11.00 km/h
B. 10.45 km/h
C. 11.24 km/h
D. 10.83 km/h
Answer: Option D
Solution (By JKSSB Mock Tests)
Total distance = 10 + 12 = 22 km. Total time taken = 10/12 + 12/10 = 5/6 + 6/5 = (25 + 36) / 30 = 61 / 30 hours. Average speed = 22 / (61/30) = 660 / 61 = 10.82 hours (approx 10.83 km/h).

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Practice More Time Speed and Distance Questions

Question #1
An emergency truck spans 450 meters in 25 seconds. Find its speed in km/h.
A. 68 km/h
B. 64.8 km/h
C. 72 km/h
D. 60 km/h

Correct Answer: Option B


Explanation:
Speed = 450 / 25 = 18 m/s. In km/h = 18 * (18/5) = 324 / 5 = 64.8 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
Two cars start from the same spot and travel along perpendicular roads. One travels at 30 km/h and the other at 40 km/h. Find the distance between them after 1 hour.
A. 45 km
B. 50 km
C. 55 km
D. 60 km

Correct Answer: Option B


Explanation:
In 1 hour, the first car travels 30 km and the second car travels 40 km. Direct distance = sqrt(30^2 + 40^2) = sqrt(900 + 1600) = sqrt(2500) = 50 km.

This question belongs to: Maths Time Speed and Distance
Question #3
Two stations A and B are 450 km apart. A train leaves station A at 4:00 PM at 60 km/h. Another train leaves station B at 5:00 PM at 70 km/h traveling towards A. At what time will they meet?
A. 9:00 PM
B. 7:30 PM
C. 8:00 PM
D. 8:30 PM

Correct Answer: Option C


Explanation:
By 5:00 PM, the first train has traveled for 1 hour and covered 60 km. Distance left between them = 450 - 60 = 390 km. Relative speed = 60 + 70 = 130 km/h. Time to meet after 5:00 PM = 390 / 130 = 3 hours. Meeting time = 5:00 PM + 3 hours = 8:00 PM.

This question belongs to: Maths Time Speed and Distance