A dog sees a cat at a distance of 150 meters. The cat starts running at 12 km/h and the dog chases it at 15 km/h. How much distance will the cat cover before being caught? MCQ with Answer and Explanation
A dog sees a cat at a distance of 150 meters. The cat starts running at 12 km/h and the dog chases it at 15 km/h. How much distance will the cat cover before being caught?
A. 900 meters
B. 500 meters
C. 600 meters
D. 750 meters
Answer: Option C
Solution (By JKSSB Mock Tests)
Relative speed = 15 - 12 = 3 km/h = 3 * (5/18) = 5/6 m/s. Time to catch = 150 / (5/6) = 180 seconds. Distance covered by cat = Speed of cat * Time = (12 * 5/18) * 180 = (10/3) * 180 = 600 meters.
A train covers a distance between two stations in 45 minutes. If its speed is reduced by 5 km/h, it covers the same distance in 48 minutes. Find the distance between the two stations.
Explanation:
Let initial speed be s. Distance is constant, so s * (45/60) = (s - 5) * (48/60) => 45s = 48s - 240 => 3s = 240 => s = 80 km/h. Distance = 80 * (45/60) = 60 km.
The speed of two cars are in the ratio 3 : 4. If the second car takes 3 hours to cover a certain distance, how much time will the first car take to cover the same distance?
Explanation:
Ratio of speeds = 3:4. Ratio of time taken (inverse of speed) = 4:3. Given 3 parts = 3 hours for the second car. Thus, 4 parts = 4 hours for the first car.
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