A fisherman rows 20 km downstream in 2 hours and 15 km upstream in 3 hours. Find the net speed of the boat in still water. MCQ with Answer and Explanation

A fisherman rows 20 km downstream in 2 hours and 15 km upstream in 3 hours. Find the net speed of the boat in still water.
A. 8.5 km/h
B. 7.5 km/h
C. 8.0 km/h
D. 7.0 km/h
Answer: Option B
Solution (By JKSSB Mock Tests)
Downstream speed = 20 / 2 = 10 km/h. Upstream speed = 15 / 3 = 5 km/h. Speed in still water = (10 + 5) / 2 = 7.5 km/h.

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Practice More Time Speed and Distance Questions

Question #1
A bus moving at 42 km/h covers a distance in 8 hours. At what speed must it travel to cover the same distance in 6 hours?
A. 64 km/h
B. 60 km/h
C. 56 km/h
D. 52 km/h

Correct Answer: Option C


Explanation:
Distance = 42 * 8 = 336 km. Required speed = 336 / 6 = 56 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
A car covers a certain distance at an average speed of 48 km/h in 5 hours. At what speed must it travel to cover the same distance in 4 hours?
A. 60 km/h
B. 70 km/h
C. 65 km/h
D. 55 km/h

Correct Answer: Option A


Explanation:
Distance = 48 * 5 = 240 km. New required speed = 240 / 4 = 60 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3
The speed index tracking profile of an express locomotive is exactly 20% higher than a commercial car. Both take off from terminal M together and reach terminal N, 120 km away, at the same instant. On the corridor route, the train logs a total stall of 10 minutes at intermediate stations. Find the car speed.
A. 100 km/h
B. 140 km/h
C. 150 km/h
D. 120 km/h

Correct Answer: Option D


Explanation:
Let car speed be c, then train tracking speed is 1.2c. Time difference parameter = 120/c - 120/(1.2c) = 10/60 hours = 1/6 hours. 120/c * (1 - 1/1.2) = 1/6 => 120/c * (0.2/1.2) = 1/6 => 120/c * (1/6) = 1/6 => c = 120 km/h.

This question belongs to: Maths Time Speed and Distance