A freely falling body exhibits which type of motion? MCQ with Answer and Explanation

A freely falling body exhibits which type of motion?
A. Non-uniform acceleration
B. Uniform velocity
C. Uniform acceleration
D. Zero acceleration
Answer: Option C
Solution (By JKSSB Mock Tests)
A freely falling body falls under the sole influence of Earth's gravity (neglecting air resistance). Near the surface of the Earth, the acceleration due to gravity ('g') is constant (approximately 9.8 m/s²). Because the acceleration does not change during the fall, it is an example of uniform accelerated motion.

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Practice More Physics Questions

Question #1
The focal length of a concave mirror is 20 cm. An object is placed at 30 cm from the mirror. The image distance is:
A. 20 cm
B. 30 cm
C. 12 cm
D. 60 cm

Correct Answer: Option D


Explanation:
Mirror formula: 1/f = 1/u + 1/v. Sign convention: f negative for concave mirror? Wait, standard Cartesian: f = -20 cm (concave), u = -30 cm (object real). Thus 1/(-20) = 1/(-30) + 1/v ⇒ -1/20 = -1/30 + 1/v ⇒ 1/v = -1/20 + 1/30 = (-3+2)/60 = -1/60 ⇒ v = -60 cm. Magnitude 60 cm, negative sign indicates real image in front of mirror. Many exams use magnitude-only options; here 60 cm is correct. Memory tip: 'Concave mirror: object beyond C (2f) ⇒ image between F and C, real, inverted'. This numerical tests mirror formula application with sign conventions, crucial for optics in competitive exams.

This question belongs to: Science Physics
Question #2
The phenomenon of persistence of sound due to multiple reflections is called
A. Echo
B. Resonance
C. Reverberation
D. Doppler effect

Correct Answer: Option C


Explanation:
Reverberation is prolongation of sound due to reflections blending. Echo is distinct repetition.

This question belongs to: Science Physics
Question #3
A brass rod of length 1 m at 0°C expands by 0.0019 m when heated to 100°C. Its linear expansion coefficient is
A. 1.9 × 10⁻³ /°C
B. 1.9 × 10⁻⁴ /°C
C. 1.9 × 10⁻⁵ /°C
D. 1.9 × 10⁻⁶ /°C

Correct Answer: Option C


Explanation:
ΔL = α L₀ ΔT => α = ΔL/(L₀ ΔT) = 0.0019/(1×100) = 1.9×10⁻⁵ /°C. Typical for brass. Unit is per °C. Always check ΔL/L per °C.

This question belongs to: Science Physics