A galvanometer can be converted into an ammeter by connecting: MCQ with Answer and Explanation

A galvanometer can be converted into an ammeter by connecting:
A. A low resistance in parallel
B. A high resistance in series
C. A high resistance in parallel
D. A low resistance in series
Answer: Option A
Solution (By JKSSB Mock Tests)
An ammeter must have very low resistance so it does not alter the circuit current it is measuring. To convert a sensitive galvanometer into an ammeter, a very low resistance called a 'shunt' is connected in parallel to it. This diverts most of the current away from the delicate galvanometer coil while still allowing a proportional measurement.

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Practice More Physics Questions

Question #1
The direction of the magnetic field lines around a straight current-carrying conductor can be determined by:
A. Faraday's Law
B. Right-Hand Thumb Rule
C. Fleming's Left-Hand Rule
D. Fleming's Right-Hand Rule

Correct Answer: Option B


Explanation:
Maxwell's Right-Hand Thumb Rule states that if you imagine holding a straight current-carrying conductor in your right hand such that the thumb points in the direction of the current, then the direction in which your fingers wrap around the conductor represents the direction of the circular magnetic field lines.

This question belongs to: Science Physics
Question #2
A cyclist moving at 18 km/h stops pedalling and comes to rest after 10 m due to friction. Deceleration is
A. 5 m/s²
B. 1.25 m/s²
C. 0.8 m/s²
D. 2.5 m/s²

Correct Answer: Option B


Explanation:
18 km/h = 5 m/s. v² = u² + 2as => 0 = 5² + 2a×10 => 25 + 20a = 0 => a = -25/20 = -1.25 m/s², deceleration = 1.25 m/s². Negative acceleration.

This question belongs to: Science Physics
Question #3
Atmospheric pressure at sea level is approximately:
A. 10³ Pa
B. 10² Pa
C. 10⁷ Pa
D. 10⁵ Pa

Correct Answer: Option D


Explanation:
Standard atmospheric pressure at sea level is 101,325 Pa, approximately 10⁵ Pa (or 1 bar, 760 mm Hg). This value is crucial for pressure calculations in fluids, thermodynamics, and meteorology. Option B (1000 Pa) is too low (about 1% of atmospheric), C and D are orders of magnitude off. Memory tip: 'Atmospheric pressure ≈ 10⁵ Pa = 100 kPa = 1 bar'. This factual knowledge is frequently tested in competitive exams as a baseline for pressure-related problems. Always use SI units (Pascal) unless specified otherwise.

This question belongs to: Science Physics