A local train spans a track sector in 40 minutes. If its speed is lowered by 6 km/h, it tracks the same sector in 45 minutes. Find the distance of this track sector. MCQ with Answer and Explanation
A local train spans a track sector in 40 minutes. If its speed is lowered by 6 km/h, it tracks the same sector in 45 minutes. Find the distance of this track sector.
A. 36 km
B. 44 km
C. 32 km
D. 40 km
Answer: Option A
Solution (By JKSSB Mock Tests)
Let original speed be s. s * (40/60) = (s - 6) * (45/60) => 40s = 45s - 270 => 5s = 270 => s = 54 km/h. Distance = 54 * (40/60) = 36 km.
A car covered a distance of 400 km at a uniform speed. If the uniform speed index is lowered by 10 km/h, the journey takes 2 hours longer. Find the original speed.
Two points P and Q are 210 km apart. Train A leaves P for Q at 50 km/h at 10:00 AM. Train B leaves Q for P at 70 km/h at 11:00 AM. At what time will they pass each other?
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