A locomotive 180 meters long crosses a modern bridge in 30 seconds. If it takes 12 seconds to pass a single post light, find the length of the bridge. MCQ with Answer and Explanation

A locomotive 180 meters long crosses a modern bridge in 30 seconds. If it takes 12 seconds to pass a single post light, find the length of the bridge.
A. 320 meters
B. 300 meters
C. 270 meters
D. 250 meters
Answer: Option C
Solution (By JKSSB Mock Tests)
Speed of train = 180 / 12 = 15 m/s. Total distance in 30 seconds = 15 * 30 = 450 meters. Length of bridge = 450 - 180 = 270 meters.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Time Speed and Distance Questions

Question #1
A man rows downstream 48 km in 4 hours and upstream 24 km in 4 hours. Find the speed of the boat in still water.
A. 12 km/h
B. 9 km/h
C. 8 km/h
D. 10 km/h

Correct Answer: Option B


Explanation:
Downstream speed = 48 / 4 = 12 km/h. Upstream speed = 24 / 4 = 6 km/h. Speed in still water = (Downstream speed + Upstream speed) / 2 = (12 + 6) / 2 = 9 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
A person has to cover a distance of 160 km. He covers the first half of the distance at 40 km/h. At what speed must he travel the remaining half to make the average speed for the whole journey 50 km/h?
A. 75 km/h
B. 70 km/h
C. 66.67 km/h
D. 60 km/h

Correct Answer: Option C


Explanation:
Let the required speed for the second half be x km/h. Using the average speed formula for equal halves: Average Speed = 2v1*v2 / (v1 + v2) => 50 = (2 * 40 * x) / (40 + x) => 50(40 + x) = 80x => 2000 + 50x = 80x => 30x = 2000 => x = 66.67 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3
Walking at 5/7 of his usual speed, a student reaches his exam center 12 minutes late. What is his exact usual time to reach the center?
A. 32 minutes
B. 30 minutes
C. 26 minutes
D. 35 minutes

Correct Answer: Option B


Explanation:
New speed = 5/7 of usual speed => New time = 7/5 of usual time. Difference = 2/5 of usual time = 12 minutes. 1/5 of usual time = 6 minutes => Usual time = 6 * 5 = 30 minutes.

This question belongs to: Maths Time Speed and Distance