A luxury car handles a tracking route sector of 240 km. It finishes the first half segment stretch at 40 km/h and the second half sector at 60 km/h. Find the mean average speed recorded across the full route. MCQ with Answer and Explanation

A luxury car handles a tracking route sector of 240 km. It finishes the first half segment stretch at 40 km/h and the second half sector at 60 km/h. Find the mean average speed recorded across the full route.
A. 48 km/h
B. 50 km/h
C. 52 km/h
D. 46 km/h
Answer: Option A
Solution (By JKSSB Mock Tests)
Average Speed across sectors = 2xy / (x + y) = (2 * 40 * 60) / (40 + 60) = 4800 / 100 = 48 km/h.

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Practice More Time Speed and Distance Questions

Question #1
A train 100 meters long running at 54 km/h passes a standing pedestrian. Find the time taken to cross.
A. 8.0 seconds
B. 7.2 seconds
C. 6.66 seconds
D. 6.0 seconds

Correct Answer: Option C


Explanation:
Speed of train = 54 * (5/18) = 15 m/s. Time taken = 100 / 15 = 6.66 seconds.

This question belongs to: Maths Time Speed and Distance
Question #2
A person leaves point A at 6:00 AM at 40 km/h. Another leaves A at 8:00 AM at 60 km/h in the same direction. At what distance from A will they meet?
A. 260 km
B. 280 km
C. 220 km
D. 240 km

Correct Answer: Option D


Explanation:
By 8:00 AM, the first person covers 40 * 2 = 80 km. Relative speed = 60 - 40 = 20 km/h. Time to meet = 80 / 20 = 4 hours. Distance from A = Speed of second person * Time = 60 * 4 = 240 km.

This question belongs to: Maths Time Speed and Distance
Question #3
A person travels from city A to city B at 50 km/h and returns at 70 km/h. What is his average speed for the round trip?
A. 61.25 km/h
B. 58.33 km/h
C. 62.5 km/h
D. 60 km/h

Correct Answer: Option B


Explanation:
Average speed = (2 * 50 * 70) / (50 + 70) = 7000 / 120 = 700 / 12 = 58.33 km/h.

This question belongs to: Maths Time Speed and Distance