A man walks from his sector quarters to a focal workshop at 4 km/h and arrives 15 minutes late. If he scales his speed to 6 km/h, he arrives 5 minutes early. Find the distance. MCQ with Answer and Explanation
A man walks from his sector quarters to a focal workshop at 4 km/h and arrives 15 minutes late. If he scales his speed to 6 km/h, he arrives 5 minutes early. Find the distance.
A. 3.5 km
B. 4.5 km
C. 5.0 km
D. 4.0 km
Answer: Option D
Solution (By JKSSB Mock Tests)
Time difference = 15 - (-5) = 20 minutes = 20/60 = 1/3 hours. Let distance be d. d/4 - d/6 = 1/3 => d/12 = 1/3 => d = 4 km.
Explanation:
Relative speed = 100 / 6 = 50/3 m/s = (50/3) * (18/5) = 60 km/h. Since the train passes him from behind (same direction), Relative Speed = Speed of train - Speed of man => 60 = Speed of train - 5 => Speed of train = 65 km/h.
A delivery car handles a total route profile of 360 km. It clears the first half stretch at 45 km/h and the second half at 90 km/h. Find the net average speed.
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