A man buys oranges at 5 for Rs. 10 and an equal number at 4 for Rs. 10. He mixes them and sells the mixture at 9 for Rs. 20. Find his profit or loss percentage. MCQ with Answer and Explanation

A man buys oranges at 5 for Rs. 10 and an equal number at 4 for Rs. 10. He mixes them and sells the mixture at 9 for Rs. 20. Find his profit or loss percentage.
A. Profit of 1.23%
B. Loss of 2.5%
C. Loss of 1.23%
D. No profit no loss
Answer: Option C
Solution (By JKSSB Mock Tests)
Buy 20 oranges of type 1 for Rs. 40. Buy 20 oranges of type 2 for Rs. 50. Total 40 oranges cost Rs. 90. Cost Price of 1 orange = 90 / 40 = 2.25. Selling Price of 9 oranges = 20. Selling Price of 1 orange = 20 / 9 = 2.222. Loss = 2.25 - 2.222 = 0.0277. Loss percentage = (0.0277 / 2.25) * 100 = 1.23% loss.

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Practice More Profit And Loss Questions

Question #1
A shopkeeper buys a product for Rs. 720 and sells it at a loss of 10%. What is the selling price?
A. Rs. 660
B. Rs. 648
C. Rs. 640
D. Rs. 650

Correct Answer: Option B


Explanation:
Loss = 10% of 720 = 72, SP = 720 - 72 = 648.

This question belongs to: Maths Profit And Loss
Question #2
If the cost price of an article is 40% of its selling price, what is the profit percentage?
A. 140%
B. 125%
C. 150%
D. 120%

Correct Answer: Option C


Explanation:
Let Selling Price = 100. Cost Price = 40. Profit = 100 - 40 = 60. Profit percentage = (60 / 40) * 100 = 150%.

This question belongs to: Maths Profit And Loss
Question #3
A man bought a chair for Rs. 600 and sold it for Rs. 720. What is the gain percent?
A. 25%
B. 20%
C. 15%
D. 30%

Correct Answer: Option B


Explanation:
Gain = 120, gain% = 120/600*100=20%.

This question belongs to: Maths Profit And Loss