A man buys oranges at 5 for Rs. 10 and an equal number at 4 for Rs. 10. He mixes them and sells the mixture at 9 for Rs. 20. Find his profit or loss percentage. MCQ with Answer and Explanation

A man buys oranges at 5 for Rs. 10 and an equal number at 4 for Rs. 10. He mixes them and sells the mixture at 9 for Rs. 20. Find his profit or loss percentage.
A. Profit of 1.23%
B. No profit no loss
C. Loss of 1.23%
D. Loss of 2.5%
Answer: Option C
Solution (By JKSSB Mock Tests)
Buy 20 oranges of type 1 for Rs. 40. Buy 20 oranges of type 2 for Rs. 50. Total 40 oranges cost Rs. 90. Cost Price of 1 orange = 90 / 40 = 2.25. Selling Price of 9 oranges = 20. Selling Price of 1 orange = 20 / 9 = 2.222. Loss = 2.25 - 2.222 = 0.0277. Loss percentage = (0.0277 / 2.25) * 100 = 1.23% loss.

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Practice More Profit And Loss Questions

Question #1
A person buys 5 kg of sugar at Rs. 35 per kg and sells at Rs. 42 per kg. What is the profit percentage?
A. 20%
B. 25%
C. 30%
D. 15%

Correct Answer: Option A


Explanation:
CP = 5*35 = 175, SP = 5*42 = 210, profit = 35, profit% = 35/175*100 = 20%.

This question belongs to: Maths Profit And Loss
Question #2
A trader sells an article for Rs. 540, gaining 8%. Find the cost price.
A. Rs. 500
B. Rs. 510
C. Rs. 520
D. Rs. 480

Correct Answer: Option A


Explanation:
CP = 540/1.08 = 500.

This question belongs to: Maths Profit And Loss
Question #3
An article is sold at Rs. 280 at a loss of 20%. What is its cost price?
A. Rs. 350
B. Rs. 360
C. Rs. 340
D. Rs. 320

Correct Answer: Option A


Explanation:
SP = 80% of CP => CP = 280/0.8 = 350.

This question belongs to: Maths Profit And Loss