A man buys oranges at 5 for Rs. 10 and an equal number at 4 for Rs. 10. He mixes them and sells them at 9 for Rs. 20. What is his profit or loss percentage? MCQ with Answer and Explanation

A man buys oranges at 5 for Rs. 10 and an equal number at 4 for Rs. 10. He mixes them and sells them at 9 for Rs. 20. What is his profit or loss percentage?
A. 1.5% Loss
B. 1% Loss
C. 1.23% Loss
D. No profit no loss
Answer: Option C
Solution (By JKSSB Mock Tests)
Let he buy 20 of each (LCM of 5 and 4). CP1 = (10/5)*20 = 40. CP2 = (10/4)*20 = 50. Total CP = 90 for 40 oranges. SP of 40 oranges = (20/9) * 40 = 800/9 = 88.88. Loss = 90 - 88.88 = 1.11. Loss % = (1.11 / 90) * 100 = 1.23%.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Profit And Loss Questions

Question #1
A person bought a watch for Rs. 2000 and sold it for Rs. 1600. What is the loss percentage?
A. 30%
B. 15%
C. 20%
D. 25%

Correct Answer: Option C


Explanation:
Loss = 400, loss% = (400/2000)*100 = 20%.

This question belongs to: Maths Profit And Loss
Question #2
If the cost price of 11 articles is equal to the selling price of 10 articles, find the gain percent.
A. 8%
B. 15%
C. 10%
D. 12%

Correct Answer: Option C


Explanation:
Let CP of 1 = 1, CP of 11 = 11, SP of 10 = 11 => SP of 1 = 11/10 = 1.1, gain = 10%.

This question belongs to: Maths Profit And Loss
Question #3
If the selling price of an article is Rs. 294 and the profit is 40%, find the cost price.
A. Rs. 220
B. Rs. 230
C. Rs. 210
D. Rs. 200

Correct Answer: Option C


Explanation:
CP = 294 / 1.40 = 210.

This question belongs to: Maths Profit And Loss