A man gave 20% of his money to his son, 30% of the remainder to his daughter, and 10% of what then remained to charity. He was left with Rs. 10080. Find the total money. MCQ with Answer and Explanation

A man gave 20% of his money to his son, 30% of the remainder to his daughter, and 10% of what then remained to charity. He was left with Rs. 10080. Find the total money.
A. Rs. 16000
B. Rs. 22000
C. Rs. 20000
D. Rs. 18000
Answer: Option C
Solution (By JKSSB Mock Tests)
Let total = T. Son 20%, left 80%. Daughter 30% of 80% = 24% of T, left 56%. Charity 10% of 56% = 5.6% of T, left 50.4% = 10080 → T = 10080/0.504 = 20000.

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Practice More Percentage Questions

Question #1
The population of a town increases by 8% annually. If its present population is 2,33,280, what was it 2 years ago?
A. 1,90,000
B. 2,10,000
C. 2,00,000
D. 1,80,000

Correct Answer: Option C


Explanation:
Pop 2 yrs ago = 233280 / (1.08)² = 233280 / 1.1664 = 200000.

This question belongs to: Maths Percentage
Question #2
A student scored 30% marks and failed by 45 marks. Another scored 42% marks and got 45 more than pass. Pass marks:
A. 225
B. 270
C. 300
D. 250

Correct Answer: Option B


Explanation:
0.3M + 45 = 0.42M - 45 → 0.12M = 90 → M=750. Pass = 0.3×750+45 = 270.

This question belongs to: Maths Percentage
Question #3
33 1/3 % of 240 is:
A. 90
B. 60
C. 80
D. 70

Correct Answer: Option C


Explanation:
33 1/3% = 1/3, (1/3)×240 = 80.

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