A man leaves point A at 6 AM at a speed of 4 km/h. Another man leaves point A from the same direction at 8 AM at a speed of 6 km/h. At what distance from point A will they meet? MCQ with Answer and Explanation
A man leaves point A at 6 AM at a speed of 4 km/h. Another man leaves point A from the same direction at 8 AM at a speed of 6 km/h. At what distance from point A will they meet?
A. 28 km
B. 24 km
C. 32 km
D. 20 km
Answer: Option B
Solution (By JKSSB Mock Tests)
By 8 AM, the first man has traveled for 2 hours, covering 4 * 2 = 8 km. Relative speed = 6 - 4 = 2 km/h. Time taken to meet = 8 / 2 = 4 hours. Distance from A = Speed of second man * Time = 6 * 4 = 24 km.
A car covers a distance of 200 km at a uniform speed. If the speed is increased by 10 km/h, the journey takes 4 hours. Find the initial speed of the car.
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