A train passes a pedestrian standing on a platform in 6 seconds and passes the platform itself, which is 150 meters long, in 11 seconds. Find the speed of the train in km/h.
Two points P and Q are 240 km apart. Train A starts from P towards Q at 60 km/h at 9:00 AM. Train B starts from Q towards P at 80 km/h at 10:00 AM. At what time will they meet?
Explanation:
By 10:00 AM, Train A covers 60 km. Remaining distance = 240 - 60 = 180 km. Relative speed = 60 + 80 = 140 km/h. Time to meet after 10 AM = 180 / 140 = 9/7 hours = 1 hour and 17 minutes. Meeting time is 11:17 AM.
A sedan covers a distance path of 480 km at a uniform tracking speed. If the speed index is lowered by 10 km/h, the trip records 2 hours longer. Find the original baseline speed.
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