A particle moves such that its position coordinates (x, y) are given by x = 2t and y = t^2. The equation of its trajectory is: MCQ with Answer and Explanation
A particle moves such that its position coordinates (x, y) are given by x = 2t and y = t^2. The equation of its trajectory is:
A. y = x^2 / 4
B. y = 2x^2
C. y = x^2 / 2
D. y = x
Answer: Option A
Solution (By JKSSB Mock Tests)
The equation of trajectory represents the path of the particle in the x-y plane, eliminating the time variable 't'. Given x = 2t, we can write t = x/2. Substitute this into the y equation: y = t^2 = (x/2)^2 = x^2 / 4. This confirms the particle moves in a parabolic path.
Explanation:
Viscosity η = Force/(Area × velocity gradient). Force [MLT⁻²], area [L²], velocity gradient [T⁻¹]. So η = [MLT⁻²]/([L²][T⁻¹]) = [ML⁻¹T⁻¹]. Often asked.
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