A pendulum has time period 2 s. If its length is increased by 4 times, new period is MCQ with Answer and Explanation

A pendulum has time period 2 s. If its length is increased by 4 times, new period is
A. 2 s
B. 1 s
C. 4 s
D. 8 s
Answer: Option C
Solution (By JKSSB Mock Tests)
T ∝ √L, L'=4L => T' = √4 T = 2×2 = 4 s.

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Practice More Physics Questions

Question #1
A transformer has 50 turns in the primary coil and 1000 turns in the secondary coil. If the primary voltage is 220V, what is the secondary voltage?
A. 22000 V
B. 4400 V
C. 440 V
D. 11 V

Correct Answer: Option B


Explanation:
The transformer equation relates voltages to the number of turns: V_secondary / V_primary = N_secondary / N_primary. We have N_p = 50, N_s = 1000, and V_p = 220V. Substituting the values gives V_s / 220 = 1000 / 50. V_s = 220 * 20 = 4400 Volts. This is a step-up transformer, increasing the voltage strictly by a factor of 20.

This question belongs to: Science Physics
Question #2
The time period of a simple pendulum is 2 s at a place where g=9.8 m/s². Its length is about
A. 2 m
B. 0.5 m
C. 0.25 m
D. 1 m

Correct Answer: Option D


Explanation:
T=2π√(L/g) => L = gT²/(4π²) ≈ (9.8×4)/(4×9.87) ≈ 1 m.

This question belongs to: Science Physics
Question #3
The work done by a conservative force in moving a particle along a closed path is:
A. Depends on path
B. Zero
C. Positive
D. Negative

Correct Answer: Option B


Explanation:
Conservative forces (gravity, spring, electrostatic) have path-independent work; work done over any closed loop is zero. This defines conservative forces and enables potential energy definition. Non-conservative forces (friction) have non-zero closed-path work. Memory aid: 'Conservative force: ∮F·dr = 0; enables energy conservation'. This mechanics concept is frequently tested in competitive exams. Always link conservative forces to potential energy and mechanical energy conservation; this is foundational for advanced physics problem-solving.

This question belongs to: Science Physics