A capillary tube is dipped in water and the water rises to a height 'h'. If the experiment is performed in a freely falling elevator, the water column in the tube will: MCQ with Answer and Explanation
A capillary tube is dipped in water and the water rises to a height 'h'. If the experiment is performed in a freely falling elevator, the water column in the tube will:
A. Rise to height h
B. Rise to height 2h
C. Rise to the full length of the capillary tube
D. Not rise at all
Answer: Option C
Solution (By JKSSB Mock Tests)
The height of capillary rise is given by Jurin's law: h = 2Tcos(theta) / (rrhog). In a freely falling elevator, the effective acceleration due to gravity (g') is zero (weightlessness). As effective g approaches zero, the theoretical height h approaches infinity. In reality, the water will rise to the very top of the tube, regardless of its length, but will not overflow.
Explanation:
Acceleration a = dv/dt = d(3t² + 2t)/dt = 6t + 2. At t = 2 s: a = 6(2) + 2 = 14 m/s². Differentiation of velocity gives instantaneous acceleration. Memory tip: a = dv/dt; for polynomial v(t), differentiate term by term. Tests calculus application in kinematics, common in advanced competitive exam questions.
Explanation:
Neutron is neutral (charge 0). Proton +e, electron -e. Alpha particle +2e. Neutron mass slightly more than proton. Discovered by Chadwick.
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