A person covers a certain distance by bicycle at a speed of 15 km/h and returns on foot at a speed of 5 km/h. If the entire trip took 4 hours, find the total distance of the one-way journey. MCQ with Answer and Explanation

A person covers a certain distance by bicycle at a speed of 15 km/h and returns on foot at a speed of 5 km/h. If the entire trip took 4 hours, find the total distance of the one-way journey.
A. 15 km
B. 20 km
C. 12 km
D. 18 km
Answer: Option A
Solution (By JKSSB Mock Tests)
Let the one-way distance be d. Time taken for forward journey = d / 15, and return journey = d / 5. Given: d/15 + d/5 = 4. Multiplying by 15: d + 3d = 60 => 4d = 60 => d = 15 km.

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Practice More Time Speed and Distance Questions

Question #1
Excluding stoppages, the speed of an inter-city bus is 45 km/h and including stoppages it is 36 km/h. How many minutes does the bus stop per hour?
A. 15 minutes
B. 18 minutes
C. 12 minutes
D. 10 minutes

Correct Answer: Option C


Explanation:
Stoppage time per hour = (45 - 36) / 45 = 9 / 45 = 1/5 hour. In minutes = (1/5) * 60 = 12 minutes.

This question belongs to: Maths Time Speed and Distance
Question #2
A person can row 6 km/h in still water. If the speed of the stream is 2 km/h, how much time will he take to row a distance of 16 km downstream?
A. 5 hours
B. 2 hours
C. 4 hours
D. 3 hours

Correct Answer: Option B


Explanation:
Downstream speed = 6 + 2 = 8 km/h. Time = Distance / Speed = 16 / 8 = 2 hours.

This question belongs to: Maths Time Speed and Distance
Question #3
A train running at 90 km/h crosses a platform double its length in 36 seconds. What is the length of the platform?
A. 500 meters
B. 600 meters
C. 750 meters
D. 400 meters

Correct Answer: Option B


Explanation:
Speed of train = 90 * (5/18) = 25 m/s. Total distance covered in 36 seconds = 25 * 36 = 900 meters. Let train length be L, so platform length = 2L. L + 2L = 900 => 3L = 900 => L = 300 meters. Platform length = 2L = 600 meters.

This question belongs to: Maths Time Speed and Distance