A person covers a certain distance by bicycle at a speed of 15 km/h and returns on foot at a speed of 5 km/h. If the entire trip took 4 hours, find the total distance of the one-way journey. MCQ with Answer and Explanation
A person covers a certain distance by bicycle at a speed of 15 km/h and returns on foot at a speed of 5 km/h. If the entire trip took 4 hours, find the total distance of the one-way journey.
A. 18 km
B. 12 km
C. 20 km
D. 15 km
Answer: Option D
Solution (By JKSSB Mock Tests)
Let the one-way distance be d. Time taken for forward journey = d / 15, and return journey = d / 5. Given: d/15 + d/5 = 4. Multiplying by 15: d + 3d = 60 => 4d = 60 => d = 15 km.
A motor car finishes a journey in 10 hours. The first half is covered at 42 km/h and the second half at 48 km/h. Find the total distance of the journey.
The speeds of two cars are in the ratio 5 : 4. If they cover the same distance, and the slower car takes 2.5 hours, how much time does the faster car take?
Explanation:
Ratio of speeds = 5:4, so ratio of times taken = 4:5. The slower car corresponds to 5 parts = 2.5 hours => 1 part = 0.5 hours. Time for the faster car = 4 parts = 4 * 0.5 = 2 hours.
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