A person leaves point A at 5:00 AM at 30 km/h. Another leaves A at 7:00 AM at 40 km/h in the same direction. At what distance from A will they meet? MCQ with Answer and Explanation
A person leaves point A at 5:00 AM at 30 km/h. Another leaves A at 7:00 AM at 40 km/h in the same direction. At what distance from A will they meet?
A. 260 km
B. 280 km
C. 220 km
D. 240 km
Answer: Option D
Solution (By JKSSB Mock Tests)
By 7:00 AM, the first person covers 30 * 2 = 60 km. Relative speed = 40 - 30 = 10 km/h. Time to meet = 60 / 10 = 6 hours. Distance from A = Speed of second person * Time = 40 * 6 = 240 km.
Two cars A and B leave an intersection simultaneously. A travels North at 45 km/h and B travels East at 60 km/h. Find the direct distance between them after 1 hour.
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