A person leaves point A at 6:00 AM at 40 km/h. Another leaves A at 8:00 AM at 60 km/h in the same direction. At what distance from A will they meet? MCQ with Answer and Explanation
A person leaves point A at 6:00 AM at 40 km/h. Another leaves A at 8:00 AM at 60 km/h in the same direction. At what distance from A will they meet?
A. 240 km
B. 220 km
C. 280 km
D. 260 km
Answer: Option A
Solution (By JKSSB Mock Tests)
By 8:00 AM, the first person covers 40 * 2 = 80 km. Relative speed = 60 - 40 = 20 km/h. Time to meet = 80 / 20 = 4 hours. Distance from A = Speed of second person * Time = 60 * 4 = 240 km.
Two points A and B are 260 km apart. Train P leaves A for B at 50 km/h at 9:00 AM. Train Q leaves B for A at 60 km/h at 10:00 AM. At what time will they cross each other?
A boatman can row 12 km/h in still water. If the river velocity index tracks at 2 km/h, find the time parameter required by the boat hull to row 40 km upstream.
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