A person reaches his destination 40 minutes late if his speed is 3 km/h, and reaches 30 minutes early if his speed is 4 km/h. Find the distance to his destination. MCQ with Answer and Explanation
A person reaches his destination 40 minutes late if his speed is 3 km/h, and reaches 30 minutes early if his speed is 4 km/h. Find the distance to his destination.
A. 16 km
B. 15 km
C. 14 km
D. 12 km
Answer: Option C
Solution (By JKSSB Mock Tests)
Time difference = 40 - (-30) = 70 minutes = 70 / 60 = 7/6 hours. Let distance be d. d/3 - d/4 = 7/6 => d/12 = 7/6 => d = 14 km.
Explanation:
Let each third of the distance be 60 km. Total distance = 180 km. Total time taken = 60/20 + 60/30 + 60/60 = 3 + 2 + 1 = 6 hours. Average speed = 180 / 6 = 30 km/h.
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