A person sets off from location M at 6:00 AM tracking at 30 km/h. Another starts from M at 8:00 AM at 50 km/h along the same direction pathway. At what distance from M do they meet? MCQ with Answer and Explanation

A person sets off from location M at 6:00 AM tracking at 30 km/h. Another starts from M at 8:00 AM at 50 km/h along the same direction pathway. At what distance from M do they meet?
A. 170 km
B. 150 km
C. 140 km
D. 160 km
Answer: Option B
Solution (By JKSSB Mock Tests)
By 8:00 AM, the first person tracks for 2 hours, covering 30 * 2 = 60 km. Relative tracking speed = 50 - 30 = 20 km/h. Time taken to meet = 60 / 20 = 3 hours. Distance covered from point M = Speed of second traveler * Meeting Time = 50 * 3 = 150 km.

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Practice More Time Speed and Distance Questions

Question #1
The speed of a train is 20% more than the speed of a car. Both start from city P at the same time and reach city Q, 120 km away, at the same time. On the way, the train stops for 10 minutes at various stations. What is the speed of the car?
A. 140 km/h
B. 100 km/h
C. 150 km/h
D. 120 km/h

Correct Answer: Option D


Explanation:
Let car speed be c, then train speed is 1.2c. Time difference = 120/c - 120/(1.2c) = 10/60 hour = 1/6 hour. 120/c * (1 - 1/1.2) = 1/6 => 120/c * (0.2/1.2) = 1/6 => 120/c * (1/6) = 1/6 => c = 120 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
A cargo train running at 64 km/h overtakes a cyclist riding at 10 km/h in the same direction in 10 seconds. Find the length of the train.
A. 150 meters
B. 140 meters
C. 160 meters
D. 180 meters

Correct Answer: Option A


Explanation:
Relative speed = 64 - 10 = 54 km/h = 54 * (5/18) = 15 m/s. Length of train = Relative speed * Time = 15 * 10 = 150 meters.

This question belongs to: Maths Time Speed and Distance
Question #3
A car covers a certain distance at 50 km/h. If the speed is increased to 75 km/h, it arrives 20 minutes earlier. Find the distance.
A. 50 km
B. 55 km
C. 45 km
D. 60 km

Correct Answer: Option A


Explanation:
Time difference = 20 minutes = 20/60 = 1/3 hour. Let distance be d. d / 50 - d / 75 = 1/3 => (3d - 2d) / 150 = 1/3 => d / 150 = 1/3 => d = 50 km.

This question belongs to: Maths Time Speed and Distance