A person travels a distance of 120 km at 40 km/h and returns at 60 km/h. Find the total time spent for the entire round trip. MCQ with Answer and Explanation

A person travels a distance of 120 km at 40 km/h and returns at 60 km/h. Find the total time spent for the entire round trip.
A. 7 hours
B. 4 hours
C. 6 hours
D. 5 hours
Answer: Option D
Solution (By JKSSB Mock Tests)
Time for onward journey = 120 / 40 = 3 hours. Time for return journey = 120 / 60 = 2 hours. Total time = 3 + 2 = 5 hours.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Time Speed and Distance Questions

Question #1
How long will a person take to walk around a square field of side 45 meters if his speed is 9 km/h?
A. 90 seconds
B. 72 seconds
C. 80 seconds
D. 64 seconds

Correct Answer: Option B


Explanation:
Perimeter of the square field = 4 * 45 = 180 meters. Speed = 9 km/h = 9 * (5/18) = 2.5 m/s. Time = Distance / Speed = 180 / 2.5 = 72 seconds.

This question belongs to: Maths Time Speed and Distance
Question #2
Two athletes run a race of 400 meters. The ratio of their speeds is 4 : 5. If the faster runner completes the race, how far ahead is he from the slower runner at that instant?
A. 100 meters
B. 60 meters
C. 120 meters
D. 80 meters

Correct Answer: Option D


Explanation:
When the faster runner covers 5 parts = 400 meters, 1 part = 80 meters. In the same time, the slower runner covers 4 parts = 4 * 80 = 320 meters. Distance between them = 400 - 320 = 80 meters.

This question belongs to: Maths Time Speed and Distance
Question #3
A person runs at 8 km/h instead of 6 km/h and consequently covers 10 km more in the same timeframe. Find the baseline distance covered at his normal speed.
A. 30 km
B. 25 km
C. 35 km
D. 40 km

Correct Answer: Option A


Explanation:
Let duration be t hours. Distance difference = 8t - 6t = 2t = 10 km => t = 5 hours. Distance handled at normal speed (6 km/h) = 6 * 5 = 30 km.

This question belongs to: Maths Time Speed and Distance