A person travels a distance of 200 km at an average speed of 50 km/h and returns at a speed of 40 km/h. Find the average speed for the round trip. MCQ with Answer and Explanation

A person travels a distance of 200 km at an average speed of 50 km/h and returns at a speed of 40 km/h. Find the average speed for the round trip.
A. 44.44 km/h
B. 42.5 km/h
C. 45.00 km/h
D. 46.25 km/h
Answer: Option A
Solution (By JKSSB Mock Tests)
Average Speed = 2xy / (x + y) = (2 * 50 * 40) / (50 + 40) = 4000 / 90 = 44.44 km/h.

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Practice More Time Speed and Distance Questions

Question #1
A person walks from home to school at 5 km/h and arrives 6 minutes late. If he runs at 6 km/h, he arrives 4 minutes early. Find the distance.
A. 4.5 km
B. 6.0 km
C. 5.0 km
D. 5.5 km

Correct Answer: Option C


Explanation:
Time difference = 6 - (-4) = 10 minutes = 10/60 = 1/6 hours. Let distance be d. d / 5 - d / 6 = 1/6 => d / 30 = 1/6 => d = 5 km.

This question belongs to: Maths Time Speed and Distance
Question #2
A motorcycle travels from terminal A to B at 40 km/h and returns at 60 km/h. What is the average speed for the round journey?
A. 50 km/h
B. 52 km/h
C. 48 km/h
D. 46 km/h

Correct Answer: Option C


Explanation:
Average Speed = 2xy / (x + y) = (2 * 40 * 60) / (40 + 60) = 4800 / 100 = 48 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3
Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train is 120 meters, in what time will they cross each other traveling in opposite directions?
A. 15 seconds
B. 12 seconds
C. 14 seconds
D. 10 seconds

Correct Answer: Option B


Explanation:
Speed of first train = 120 / 10 = 12 m/s. Speed of second train = 120 / 15 = 8 m/s. Total distance to cross each other = 120 + 120 = 240 meters. Relative speed in opposite directions = 12 + 8 = 20 m/s. Time = 240 / 20 = 12 seconds.

This question belongs to: Maths Time Speed and Distance