A person travels from P to Q at a speed of 30 km/h and returns from Q to P at a speed of 40 km/h. What is the ratio of time taken by him in the forward journey to that in the return journey? MCQ with Answer and Explanation

A person travels from P to Q at a speed of 30 km/h and returns from Q to P at a speed of 40 km/h. What is the ratio of time taken by him in the forward journey to that in the return journey?
A. 4:3
B. 16:9
C. 9:16
D. 3:4
Answer: Option A
Solution (By JKSSB Mock Tests)
Since distance is constant, time is inversely proportional to speed. Ratio of times = Speed2 : Speed1 = 40 : 30 = 4:3.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Time Speed and Distance Questions

Question #1
A luxury car handles a tracking route sector of 240 km. It finishes the first half segment stretch at 40 km/h and the second half sector at 60 km/h. Find the mean average speed recorded across the full route.
A. 48 km/h
B. 50 km/h
C. 52 km/h
D. 46 km/h

Correct Answer: Option A


Explanation:
Average Speed across sectors = 2xy / (x + y) = (2 * 40 * 60) / (40 + 60) = 4800 / 100 = 48 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
A person covers a distance of 12 km in 1 hour 30 minutes. What is his speed in meters per second?
A. 2.50 m/s
B. 2.00 m/s
C. 2.22 m/s
D. 2.77 m/s

Correct Answer: Option C


Explanation:
Time = 1.5 hours. Speed = 12 / 1.5 = 8 km/h. To convert into m/s, multiply by 5/18. Speed = 8 * (5/18) = 40 / 18 = 2.22 m/s.

This question belongs to: Maths Time Speed and Distance
Question #3
A passenger train running at 54 km/h passes through a tunnel 400 meters long in 40 seconds. Find the length of the train.
A. 220 meters
B. 200 meters
C. 240 meters
D. 180 meters

Correct Answer: Option B


Explanation:
Speed of train = 54 * (5/18) = 15 m/s. Total distance covered in 40 seconds = 15 * 40 = 600 meters. Length of train = Total distance - Tunnel length = 600 - 400 = 200 meters.

This question belongs to: Maths Time Speed and Distance