A person travels from P to Q at a speed of 30 km/h and returns from Q to P at a speed of 40 km/h. What is the ratio of time taken by him in the forward journey to that in the return journey? MCQ with Answer and Explanation
A person travels from P to Q at a speed of 30 km/h and returns from Q to P at a speed of 40 km/h. What is the ratio of time taken by him in the forward journey to that in the return journey?
A. 16:9
B. 9:16
C. 4:3
D. 3:4
Answer: Option C
Solution (By JKSSB Mock Tests)
Since distance is constant, time is inversely proportional to speed. Ratio of times = Speed2 : Speed1 = 40 : 30 = 4:3.
Excluding regular route passenger stops, the speed of an express coach is 64 km/h and including stops it is 48 km/h. For how many minutes does the coach stop per hour?
A delivery coach covers a highway stretch at 40 km/h. If the driver spikes the speed index to 60 km/h, the coach lands at the station terminal 15 minutes early. Find the track sector distance.
Explanation:
Time difference = 15 minutes = 15/60 = 1/4 hours. Let distance be d. d / 40 - d / 60 = 1/4 => (3d - 2d) / 120 = 1/4 => d / 120 = 1/4 => d = 30 km.
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