A person walking at 4/5 of his usual speed reaches his shop 15 minutes late. What is his usual time to reach the shop? MCQ with Answer and Explanation

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A person walking at 4/5 of his usual speed reaches his shop 15 minutes late. What is his usual time to reach the shop?

A. 80 minutes

B. 50 minutes

C. 70 minutes

D. 60 minutes

Answer: Option D

Solution (By JKSSB Mock Tests)

New speed = 4/5 of usual speed => New time = 5/4 of usual time. Difference = 1/4 of usual time = 15 minutes. Usual time = 15 * 4 = 60 minutes.

This question belongs to: Maths Time Speed and Distance

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Question #1

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A person can walk at 6 km/h. How many meters can he cover in 15 minutes?

A. 1400 meters

B. 1800 meters

C. 1600 meters

D. 1500 meters

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Correct Answer: Option D

Explanation:
Speed = 6 km/h = 6000 meters / 60 minutes = 100 meters per minute. Distance in 15 minutes = 100 * 15 = 1500 meters.

This question belongs to: Maths Time Speed and Distance

Question #2

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In a 500-meter dash trial heat, runner A clocks across the tape in 50 seconds, while runner B marks a finish layout in 55 seconds. By what distance does runner A beat runner B?

A. 48.25 meters

B. 50.00 meters

C. 42.34 meters

D. 45.45 meters

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Correct Answer: Option D

Explanation:
Speed of runner B = 500 / 55 = 100 / 11 m/s. Distance covered by runner B when runner A finishes at 50 seconds = (100 / 11) * 50 = 5000 / 11 = 454.54 meters. Margin distance = 500 - 454.54 = 45.45 meters.

This question belongs to: Maths Time Speed and Distance