A person walks from his house to office at 5 km/h and arrives 10 minutes late. If he walks at 6 km/h, he arrives 4 minutes late. Find the distance. MCQ with Answer and Explanation

A person walks from his house to office at 5 km/h and arrives 10 minutes late. If he walks at 6 km/h, he arrives 4 minutes late. Find the distance.
A. 4.0 km
B. 2.5 km
C. 3.0 km
D. 3.5 km
Answer: Option C
Solution (By JKSSB Mock Tests)
Time difference = 10 - 4 = 6 minutes = 6/60 = 0.1 hours. Let distance be d. d / 5 - d / 6 = 0.1 => d / 30 = 0.1 => d = 3 km.

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Practice More Time Speed and Distance Questions

Question #1
A man covers 1/3 of his total journey at 30 km/h and the remaining 2/3 at 60 km/h. Find his average speed for the entire journey.
A. 52 km/h
B. 48 km/h
C. 50 km/h
D. 45 km/h

Correct Answer: Option B


Explanation:
Let total distance be 90 km. First part = 30 km; Time = 30 / 30 = 1 hour. Remaining part = 60 km; Time = 60 / 60 = 1 hour. Total distance = 90 km, Total time = 2 hours. Average speed = 90 / 2 = 45 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
A cyclist handles 600 meters in exactly 2 minutes. Find his moving velocity in km/h.
A. 20 km/h
B. 15 km/h
C. 18 km/h
D. 22 km/h

Correct Answer: Option C


Explanation:
Time = 2 minutes = 120 seconds. Speed = 600 / 120 = 5 m/s. In km/h = 5 * (18/5) = 18 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3
Excluding stoppages, a bus travels at 54 km/h and including stoppages it travels at 45 km/h. How many minutes does the bus stop per hour?
A. 12 minutes
B. 15 minutes
C. 8 minutes
D. 10 minutes

Correct Answer: Option D


Explanation:
Stoppage time per hour = (54 - 45) / 54 = 9 / 54 = 1/6 hour. In minutes = (1/6) * 60 = 10 minutes.

This question belongs to: Maths Time Speed and Distance