A person walks from his house to office at 5 km/h and arrives 10 minutes late. If he walks at 6 km/h, he arrives 4 minutes late. Find the distance. MCQ with Answer and Explanation

Question

A person walks from his house to office at 5 km/h and arrives 10 minutes late. If he walks at 6 km/h, he arrives 4 minutes late. Find the distance.

A. 3.0 km

B. 2.5 km

C. 4.0 km

D. 3.5 km

Answer: Option A

Solution (By JKSSB Mock Tests)

Time difference = 10 - 4 = 6 minutes = 6/60 = 0.1 hours. Let distance be d. d / 5 - d / 6 = 0.1 => d / 30 = 0.1 => d = 3 km.

This question belongs to: Maths Time Speed and Distance

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Question #1

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A cart wheel turns 1000 revolutions to bridge a sector distance of 1320 meters. Find the diameter size of the turning wheel.

A. 42 cm

B. 46 cm

C. 38 cm

D. 50 cm

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Correct Answer: Option A

Explanation:
Distance covered in 1 single turn revolution = 1320 / 1000 = 1.32 meters = 132 cm. Circumference = 2 * (22/7) * r = 132 cm => Diameter (2r) * (22/7) = 132 => Diameter = 132 * 7 / 22 = 6 * 7 = 42 cm.

This question belongs to: Maths Time Speed and Distance

Question #2

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A man covers 1/3rd of his journey at 20 km/h and the remaining 2/3rd at 40 km/h. If the total distance is 120 km, find the total time taken for the journey.

A. 5 hours

B. 4.5 hours

C. 3.5 hours

D. 4 hours

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Correct Answer: Option D

Explanation:
First part distance = 120 / 3 = 40 km. Time1 = 40 / 20 = 2 hours. Remaining distance = 80 km. Time2 = 80 / 40 = 2 hours. Total time = 2 + 2 = 4 hours.

This question belongs to: Maths Time Speed and Distance

Question #3

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A man covers a certain distance by car driving at 40 km/h and returns back to the starting point riding on a scooter at 10 km/h. Find his average speed for the whole journey.

A. 25 km/h

B. 16 km/h

C. 30 km/h

D. 20 km/h

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Correct Answer: Option B

Explanation:
When equal distances are covered at two different speeds x and y, Average Speed = 2xy / (x + y). Here, Average Speed = (2 * 40 * 10) / (40 + 10) = 800 / 50 = 16 km/h.

This question belongs to: Maths Time Speed and Distance

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