A person walks from his house to office at 5 km/h and arrives 12 minutes late. If he walks at 6 km/h, he arrives 2 minutes late. Find the distance. MCQ with Answer and Explanation

Question

A person walks from his house to office at 5 km/h and arrives 12 minutes late. If he walks at 6 km/h, he arrives 2 minutes late. Find the distance.

A. 6.0 km

B. 5.5 km

C. 4.5 km

D. 5.0 km

Answer: Option D

Solution (By JKSSB Mock Tests)

Time difference = 12 - 2 = 10 minutes = 10/60 = 1/6 hours. Let distance be d. d / 5 - d / 6 = 1/6 => d / 30 = 1/6 => d = 5 km.

This question belongs to: Maths Time Speed and Distance

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Question #1

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A car covers three successive 10 km stretches at speeds of 20 km/h, 30 km/h and 60 km/h respectively. Find its average speed.

A. 32 km/h

B. 28 km/h

C. 30 km/h

D. 35 km/h

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Correct Answer: Option C

Explanation:
Total distance = 3 * 10 = 30 km. Total time taken = 10/20 + 10/30 + 10/60 = 1/2 + 1/3 + 1/6 = 1 hour. Average speed = 30 / 1 = 30 km/h.

This question belongs to: Maths Time Speed and Distance

Question #2

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The speed of a train is 90 km/h. How many meters does it cross in exactly 12 seconds?

A. 350 meters

B. 320 meters

C. 300 meters

D. 280 meters

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Correct Answer: Option C

Explanation:
Speed = 90 * (5/18) = 25 m/s. Distance in 12 seconds = Speed * Time = 25 * 12 = 300 meters.

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Question #3

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A train running at 72 km/h passes an active signal pole in 10 seconds. Find the length of the train.

A. 220 meters

B. 240 meters

C. 180 meters

D. 200 meters

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Correct Answer: Option D

Explanation:
Speed = 72 * (5/18) = 20 m/s. Length of train = Speed * Time = 20 * 10 = 200 meters.

This question belongs to: Maths Time Speed and Distance

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