A photon of energy 3.3 eV has frequency approximately (h=4.14×10⁻¹⁵ eV s) MCQ with Answer and Explanation

A photon of energy 3.3 eV has frequency approximately (h=4.14×10⁻¹⁵ eV s)
A. 3×10⁸ Hz
B. 8×10¹⁴ Hz
C. 5×10¹⁴ Hz
D. 1.25×10¹⁵ Hz
Answer: Option B
Solution (By JKSSB Mock Tests)
f = E/h = 3.3 / 4.14×10⁻¹⁵ ≈ 8×10¹⁴ Hz.

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