A private sedan tracks a sector path length of 480 km in 5 hours 20 minutes. Find its mean average speed index. MCQ with Answer and Explanation

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A private sedan tracks a sector path length of 480 km in 5 hours 20 minutes. Find its mean average speed index.

A. 95 km/h

B. 85 km/h

C. 100 km/h

D. 90 km/h

Answer: Option D

Solution (By JKSSB Mock Tests)

Time = 5 hours 20 minutes = 5 + 20/60 = 5.333 hours = 16/3 hours. Speed index = Sector Distance / Time = 480 / (16/3) = 480 * 3 / 16 = 30 * 3 = 90 km/h.

This question belongs to: Maths Time Speed and Distance

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Two outposts M and N are 320 km apart. Train A leaves M for N at 40 km/h at 6:00 AM. Train B leaves N for M at 60 km/h at 8:00 AM. At what time will they cross?

A. 10:36 AM

B. 10:24 AM

C. 10:48 AM

D. 10:12 AM

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Correct Answer: Option B

Explanation:
By 8:00 AM, Train A has run for 2 hours, covering 40 * 2 = 80 km. Remaining separation distance = 320 - 80 = 240 km. Relative speed = 40 + 60 = 100 km/h. Time after 8:00 AM = 240 / 100 = 2.4 hours = 2 hours 24 minutes. Meeting time = 8:00 AM + 2 hours 24 minutes = 10:24 AM.

This question belongs to: Maths Time Speed and Distance