A projectile is fired at an angle of 45 degrees to the horizontal. The ratio of its maximum height to its horizontal range is:

Question

Team JKSSB Mock Tests · Accepted Answer

The maximum height H = (u^2 * sin^2(theta)) / 2g. The horizontal range R = (u^2 * sin(2theta)) / g. For an angle of 45 degrees, sin(45) = 1/sqrt(2) and sin(90) = 1. H = (u^2 * 0.5) / 2g = u^2 / 4g. R = u^2 / g. Therefore, H/R = (u^2/4g) / (u^2/g) = 1/4. The ratio is 1:4.

A projectile is fired at an angle of 45 degrees to the horizontal. The ratio of its maximum height to its horizontal range is: MCQ with Answer and Explanation

Solution (By JKSSB Mock Tests)

Discuss this Question (0)

Practice More Physics Questions