A radioactive sample has a half-life of 5 years. What fraction of the original active nuclei will remain undecayed after 15 years? MCQ with Answer and Explanation

A radioactive sample has a half-life of 5 years. What fraction of the original active nuclei will remain undecayed after 15 years?
A. 1/8
B. 1/3
C. 1/15
D. 1/2
Answer: Option A
Solution (By JKSSB Mock Tests)
The number of half-lives (n) that have passed is total time / half-life = 15 / 5 = 3 half-lives. The fraction of the sample remaining undecayed is given strictly by the formula (1/2)^n. Therefore, the fraction remaining is (1/2)^3 = 1/2 * 1/2 * 1/2 = 1/8.

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Practice More Physics Questions

Question #1
The focal length of a concave mirror is 10 cm. Object placed at 20 cm gives image distance
A. 5 cm
B. 10 cm
C. Infinity
D. 20 cm

Correct Answer: Option D


Explanation:
u = -20, f = -10. Mirror formula: 1/f = 1/v + 1/u => 1/(-10) = 1/v + 1/(-20) => -1/10 = 1/v - 1/20 => 1/v = -1/10 + 1/20 = -1/20 => v = -20 cm, image at C.

This question belongs to: Science Physics
Question #2
A force of 20 N acts on a body of mass 4 kg for 5 s. Change in momentum is
A. 100 kg m/s
B. 4 kg m/s
C. 80 kg m/s
D. 20 kg m/s

Correct Answer: Option A


Explanation:
Impulse = F×t = 20×5 = 100 N s = change in momentum.

This question belongs to: Science Physics
Question #3
A car travels first half distance at 40 km/h and second half at 60 km/h. Average speed is
A. 52 km/h
B. 48 km/h
C. 45 km/h
D. 50 km/h

Correct Answer: Option B


Explanation:
Average speed = 2v₁v₂/(v₁+v₂) = 2×40×60/(40+60) = 4800/100 = 48 km/h. Not arithmetic mean (50). For equal distances, harmonic mean of speeds. If times equal, arithmetic mean applies.

This question belongs to: Science Physics