A runner covers 200 meters in 22 seconds. Find his approximate speed in km/h. MCQ with Answer and Explanation

A runner covers 200 meters in 22 seconds. Find his approximate speed in km/h.
A. 36.0 km/h
B. 30.5 km/h
C. 32.7 km/h
D. 34.2 km/h
Answer: Option C
Solution (By JKSSB Mock Tests)
Speed = 200 / 22 m/s = 100 / 11 m/s. In km/h = (100 / 11) * (18/5) = 360 / 11 = 32.72 km/h.

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Practice More Time Speed and Distance Questions

Question #1
Two outposts M and N are 320 km apart. Train A leaves M for N at 40 km/h at 6:00 AM. Train B leaves N for M at 60 km/h at 8:00 AM. At what time will they cross?
A. 10:24 AM
B. 10:48 AM
C. 10:12 AM
D. 10:36 AM

Correct Answer: Option A


Explanation:
By 8:00 AM, Train A has run for 2 hours, covering 40 * 2 = 80 km. Remaining separation distance = 320 - 80 = 240 km. Relative speed = 40 + 60 = 100 km/h. Time after 8:00 AM = 240 / 100 = 2.4 hours = 2 hours 24 minutes. Meeting time = 8:00 AM + 2 hours 24 minutes = 10:24 AM.

This question belongs to: Maths Time Speed and Distance
Question #2
A person walks from his residence to his office at 4 km/h and arrives 15 minutes late. If he increases his speed to 6 km/h, he still arrives 5 minutes late. Find the distance.
A. 3 km
B. 1.5 km
C. 2 km
D. 2.5 km

Correct Answer: Option C


Explanation:
Time difference = 15 - 5 = 10 minutes = 10 / 60 = 1/6 hour. Let distance be d. d/4 - d/6 = 1/6 => d/12 = 1/6 => d = 2 km.

This question belongs to: Maths Time Speed and Distance
Question #3
A courier driver logs 3 hours at 50 km/h and the next 2 hours at 60 km/h. Find the combined average speed.
A. 52 km/h
B. 54 km/h
C. 55 km/h
D. 56 km/h

Correct Answer: Option B


Explanation:
Distance 1 = 50 * 3 = 150 km. Distance 2 = 60 * 2 = 120 km. Total distance = 270 km. Total time = 5 hours. Average speed = 270 / 5 = 54 km/h.

This question belongs to: Maths Time Speed and Distance