A runner tracks a circular field of circumference 600 meters. If his speed is 14.4 km/h, how many rounds can he complete in 15 minutes? MCQ with Answer and Explanation

A runner tracks a circular field of circumference 600 meters. If his speed is 14.4 km/h, how many rounds can he complete in 15 minutes?
A. 7 rounds
B. 8 rounds
C. 6 rounds
D. 5 rounds
Answer: Option C
Solution (By JKSSB Mock Tests)
Speed = 14.4 km/h = 14.4 * (5/18) = 4 m/s. Time = 15 minutes = 900 seconds. Total distance wrapped = 4 * 900 = 3600 meters. Number of rounds completed = 3600 / 600 = 6 rounds.

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Practice More Time Speed and Distance Questions

Question #1
A train passes a 150-meter long bridge in 15 seconds and a standard sign post in 9 seconds. Find the length of the train.
A. 210 meters
B. 225 meters
C. 240 meters
D. 250 meters

Correct Answer: Option B


Explanation:
Time taken to cross the bridge alone = 15 - 9 = 6 seconds. Speed of train = 150 / 6 = 25 m/s. Length of train = Speed * Time to cross sign post = 25 * 9 = 225 meters.

This question belongs to: Maths Time Speed and Distance
Question #2
In a 1000m dash, competitor M beats B by 80 meters, and B beats C by 50 meters. Assuming uniform velocities, by how many meters does M beat C in that same race?
A. 126 meters
B. 122 meters
C. 130 meters
D. 134 meters

Correct Answer: Option A


Explanation:
When M runs 1000m, B runs 920m. When B runs 1000m, C runs 950m. When B runs 920m, C runs 950 * (920/1000) = 95 * 9.2 = 874m. Therefore, M beats C by 1000 - 874 = 126 meters.

This question belongs to: Maths Time Speed and Distance
Question #3
A train starts from Delhi at 6:00 AM and reaches Ambala at 10:00 AM. Another train starts from Ambala at 8:00 AM and reaches Delhi at 11:30 AM. At what time do the two trains cross each other?
A. 8:56 AM
B. 9:24 AM
C. 9:12 AM
D. 9:36 AM

Correct Answer: Option A


Explanation:
Train 1 takes 4 hours, Train 2 takes 3.5 hours (7/2 hours). Let distance be LCM(4, 3.5) = 28 units. Speed of Train 1 = 7 units/h, Speed of Train 2 = 8 units/h. By 8:00 AM, Train 1 travels 2 hours * 7 = 14 units. Remaining distance = 28 - 14 = 14 units. Relative speed = 7 + 8 = 15 units/h. Time to meet after 8 AM = 14/15 hours = 56 minutes. Meeting time = 8:56 AM.

This question belongs to: Maths Time Speed and Distance