A runner tracks a circular field of radius 140 meters. If his speed is 5 m/s, how long does he take to complete a single lap? MCQ with Answer and Explanation

A runner tracks a circular field of radius 140 meters. If his speed is 5 m/s, how long does he take to complete a single lap?
A. 192 seconds
B. 160 seconds
C. 180 seconds
D. 176 seconds
Answer: Option D
Solution (By JKSSB Mock Tests)
Circumference = 2 * (22/7) * 140 = 880 meters. Time taken = Distance / Speed = 880 / 5 = 176 seconds.

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Practice More Time Speed and Distance Questions

Question #1
A train 140 meters long passes a roadside platform 260 meters long in 20 seconds. Find the speed of the train in km/h.
A. 80 km/h
B. 72 km/h
C. 76 km/h
D. 68 km/h

Correct Answer: Option B


Explanation:
Total distance = 140 + 260 = 400 meters. Speed = 400 / 20 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
A locomotive express train passes a milestone column track point in 10 seconds flat. If the speed index of the train records at 54 km/h, find the length of the train layout.
A. 135 meters
B. 150 meters
C. 165 meters
D. 180 meters

Correct Answer: Option B


Explanation:
Speed of train = 54 * (5/18) = 15 m/s. Length of train layout = Speed * Time = 15 * 10 = 150 meters.

This question belongs to: Maths Time Speed and Distance
Question #3
A train covers a distance of 360 km at a uniform speed. If the speed had been 10 km/h more, it would have taken 3 hours less for the same journey. What is the original speed of the train?
A. 25 km/h
B. 30 km/h
C. 35 km/h
D. 40 km/h

Correct Answer: Option B


Explanation:
Let original speed be s. 360/s - 360/(s+10) = 3. Dividing by 3: 120/s - 120/(s+10) = 1. 120(s + 10 - s) = s(s + 10) => 1200 = s(s + 10). Solving s^2 + 10s - 1200 = 0 gives (s-30)(s+40) = 0. Since speed is positive, s = 30 km/h.

This question belongs to: Maths Time Speed and Distance