A spring of spring constant k is cut into four equal parts. The spring constant of each part is MCQ with Answer and Explanation

Explanation:
v_max = ωA = (2π/T) A = (2π/2)×5 = 5π cm/s.

Explanation:
The magnetic Lorentz force on a moving charge is F = q(v x B) = qvBsin(theta). If the particle moves completely parallel to the magnetic field, the angle theta is 0 degrees. Since sin(0) = 0, the magnetic force is absolutely zero. Experiencing no transverse force, the particle continues moving in a perfect straight line.

Explanation:
Maximum friction = μN = 0.4×50 = 20 N. Weight = 50 N. Friction < weight, so block will fall. Wait, force 50 N horizontal, weight 5×10=50 N. Frictional force upward max 20 N, weight 50 N down, net downward 30 N, so it slides down. So it falls down. Answer A. Let's correct: option A: Falls down. I'll set A.