A spring with k=200 N/m is compressed by 0.1 m. Potential energy stored is MCQ with Answer and Explanation

Question

Share Report Error

A spring with k=200 N/m is compressed by 0.1 m. Potential energy stored is

A. 2 J

B. 20 J

C. 1 J

D. 0.5 J

Answer: Option C

Solution (By JKSSB Mock Tests)

U = ½ k x² = ½×200×0.01 = 1 J.

This question belongs to: Science Physics

Request complete Subject PDF

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Physics Questions

Question #1

Share Report

A transformer steps up 220 V to 2200 V. The turn ratio (secondary to primary) is

A. 1:10

B. 1:1

C. 220:1

D. 10:1

View Answer & Solution Discuss

Get Complete Subject PDF for Science

Correct Answer: Option D

Explanation:
For ideal transformer, V_s/V_p = N_s/N_p. So N_s/N_p = 2200/220 = 10. So secondary turns 10 times primary. Ratio 10:1. Step-up increases voltage.

This question belongs to: Science Physics

Question #2

Share Report

Carnot efficiency η = 1 - T₂/T₁. If T₁=600K, T₂=300K, η is:

A. 75%

B. 100%

C. 25%

D. 50%

View Answer & Solution Discuss

Get Complete Subject PDF for Science

Correct Answer: Option D

Explanation:
η = 1 - 300/600 = 1 - 0.5 = 0.5 = 50%. Maximum possible efficiency for given temperatures. Memory aid: 'η_Carnot = 1 - T_cold/T_hot; always < 100%'. Thermodynamics calculation frequently tested in competitive exams.

This question belongs to: Science Physics

Question #3

Share Report

Three 3Ω resistors in parallel: equivalent resistance is:

A. 0.33Ω

B. 3Ω

C. 9Ω

D. 1Ω

View Answer & Solution Discuss

Get Complete Subject PDF for Science

Correct Answer: Option D

Explanation:
1/R_eq = 1/3 + 1/3 + 1/3 = 1 ⇒ R_eq = 1Ω. For n equal resistors in parallel: R_eq = R/n. Memory tip: 'Parallel: reciprocal sum; result < smallest resistor'. Basic circuit calculation frequently tested in competitive exams to verify parallel combination formula.

This question belongs to: Science Physics

Explore All Physics MCQs