A sprinter tracks a 100-meter course in 10 seconds, while the runner-up completes it in 11 seconds. By what distance does the winner beat the runner-up? MCQ with Answer and Explanation

A sprinter tracks a 100-meter course in 10 seconds, while the runner-up completes it in 11 seconds. By what distance does the winner beat the runner-up?
A. 9.50 meters
B. 10.00 meters
C. 8.50 meters
D. 9.09 meters
Answer: Option D
Solution (By JKSSB Mock Tests)
Speed of runner-up = 100 / 11 m/s. Distance covered by runner-up in 10 seconds = (100 / 11) * 10 = 1000 / 11 = 90.91 meters. Margin = 100 - 90.91 = 9.09 meters.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Time Speed and Distance Questions

Question #1
A person travels a distance of 300 km at an average speed of 60 km/h and returns at a speed of 40 km/h. Find the average speed for the round trip.
A. 48 km/h
B. 50 km/h
C. 46 km/h
D. 52 km/h

Correct Answer: Option A


Explanation:
Average Speed = 2xy / (x + y) = (2 * 60 * 40) / (60 + 40) = 4800 / 100 = 48 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
Two sprinters race on a 200-meter straight track. The ratio of their speeds is 4 : 5. When the winner crosses the finish line, how far away from the tape is the slower sprinter?
A. 50 meters
B. 40 meters
C. 30 meters
D. 60 meters

Correct Answer: Option B


Explanation:
The faster sprinter covers 5 parts = 200 meters, so 1 part = 40 meters. In that same timeframe, the slower sprinter covers 4 parts = 4 * 40 = 160 meters. Distance remaining for the slower sprinter = 200 - 160 = 40 meters.

This question belongs to: Maths Time Speed and Distance
Question #3
A car travels the first half of a total distance at speed v1 and the second half at speed v2. What is the expression for the average speed of the car?
A. v1*v2 / (v1 + v2)
B. (v1 + v2) / 2
C. 2 / (v1 + v2)
D. 2v1*v2 / (v1 + v2)

Correct Answer: Option D


Explanation:
When equal distances are traveled at speeds v1 and v2, the average speed is the harmonic mean: 2v1*v2 / (v1 + v2).

This question belongs to: Maths Time Speed and Distance