A student walks from his quarter block to the academy center at 4 km/h and arrives 8 minutes late. If he manages a pace of 5 km/h, he arrives 4 minutes early. Find the track distance. MCQ with Answer and Explanation
A student walks from his quarter block to the academy center at 4 km/h and arrives 8 minutes late. If he manages a pace of 5 km/h, he arrives 4 minutes early. Find the track distance.
A. 4.5 km
B. 5.0 km
C. 4.0 km
D. 3.5 km
Answer: Option C
Solution (By JKSSB Mock Tests)
Time difference = 8 - (-4) = 12 minutes = 10/60 = 1/5 hours. Let distance be d. d/4 - d/5 = 1/5 => d/20 = 1/5 => d = 4 km.
A man covers 3/5 of his journey at 60 km/h, 1/4 of his journey at 40 km/h and the remaining journey at 20 km/h. Find his average speed for the whole transaction.
Explanation:
Let total distance be 400 km. First part = 240 km; Time = 240/60 = 4 hours. Second part = 100 km; Time = 100/40 = 2.5 hours. Remaining distance = 400 - 240 - 100 = 60 km; Time = 60/20 = 3 hours. Total time = 4 + 2.5 + 3 = 9.5 hours. Average speed = 400 / 9.5 = 4000 / 95 = 46.15 km/h.
A dispatch rider travels between two depots at a speed of 50 km/h and arrives on schedule. If he travels at 40 km/h, he is late by 45 minutes. Find the distance between the two depots.
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