A thief escapes at 5:00 AM at 40 km/h. The police pursue him starting at 6:00 AM at 50 km/h. At what time will the thief be apprehended? MCQ with Answer and Explanation
A thief escapes at 5:00 AM at 40 km/h. The police pursue him starting at 6:00 AM at 50 km/h. At what time will the thief be apprehended?
A. 10:30 AM
B. 11:00 AM
C. 10:00 AM
D. 9:30 AM
Answer: Option C
Solution (By JKSSB Mock Tests)
By 6:00 AM, the thief has traveled for 1 hour and covered 40 km. Relative speed = 50 - 40 = 10 km/h. Time taken to catch = 40 / 10 = 4 hours. Capture time = 6:00 AM + 4 hours = 10:00 AM.
A car travels a distance of 420 km at a certain speed. If the speed is increased by 15 km/h, it takes 5 hours for the journey. Find the original speed.
Explanation:
New speed = 5/6 of usual speed => New time = 6/5 of usual time. Difference = 1/5 of usual time = 15 minutes. Typical baseline time parameter = 15 * 5 = 75 minutes.
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