A thief escapes from police custody at 1:00 PM running at 45 km/h. The police discover the escape at 1:20 PM and start chasing him at 60 km/h. At what time will the police catch the thief? MCQ with Answer and Explanation
A thief escapes from police custody at 1:00 PM running at 45 km/h. The police discover the escape at 1:20 PM and start chasing him at 60 km/h. At what time will the police catch the thief?
A. 2:20 PM
B. 2:00 PM
C. 2:30 PM
D. 3:00 PM
Answer: Option A
Solution (By JKSSB Mock Tests)
In 20 minutes (1/3 hour), the thief covers 45 * (1/3) = 15 km. Relative speed = 60 - 45 = 15 km/h. Time taken to catch = 15 / 15 = 1 hour. Catching time = 1:20 PM + 1 hour = 2:20 PM.
Two locomotive train units of equal layout lengths pass a single track sign pole in 10 seconds and 15 seconds. If each train length tracks at 120 meters, find the time parameter to pass each other completely when running in opposite directions.
Two points A and B are 260 km apart. Train P leaves A for B at 50 km/h at 9:00 AM. Train Q leaves B for A at 60 km/h at 10:00 AM. At what time will they cross each other?
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