A track sprinter matches a 300-meter straight heat in 30 seconds. Find his moving speed in km/h. MCQ with Answer and Explanation

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A track sprinter matches a 300-meter straight heat in 30 seconds. Find his moving speed in km/h.

A. 44 km/h

B. 40 km/h

C. 32 km/h

D. 36 km/h

Answer: Option D

Solution (By JKSSB Mock Tests)

Speed in m/s = 300 / 30 = 10 m/s. In km/h = 10 * (18/5) = 36 km/h.

This question belongs to: Maths Time Speed and Distance

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Question #1

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A train 100 meters long passes a static observer in 5 seconds. How long will it take to pass a platform 260 meters long?

A. 22 seconds

B. 18 seconds

C. 16 seconds

D. 20 seconds

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Correct Answer: Option B

Explanation:
Speed of train = 100 / 5 = 20 m/s. Total distance to pass platform = 100 + 260 = 360 meters. Time taken = 360 / 20 = 18 seconds.

This question belongs to: Maths Time Speed and Distance

Question #2

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The speed of a train is 20% more than the speed of a car. Both start from point A at the same time and reach point B, 120 km away, at the same time. On the way, however, the train lost about 10 minutes while stopping at the stations. What is the speed of the car?

A. 140 km/h

B. 100 km/h

C. 80 km/h

D. 120 km/h

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Correct Answer: Option D

Explanation:
Let car speed be c, then train speed is 1.2c. Time difference = 120/c - 120/(1.2c) = 10/60 hour. 120/c * (1 - 1/1.2) = 1/6 => 120/c * (0.2/1.2) = 1/6 => 120/c * (1/6) = 1/6 => c = 120 km/h.

This question belongs to: Maths Time Speed and Distance