A train 100 meters long passes a static observer in 5 seconds. How long will it take to pass a platform 260 meters long? MCQ with Answer and Explanation

A train 100 meters long passes a static observer in 5 seconds. How long will it take to pass a platform 260 meters long?
A. 16 seconds
B. 18 seconds
C. 20 seconds
D. 22 seconds
Answer: Option B
Solution (By JKSSB Mock Tests)
Speed of train = 100 / 5 = 20 m/s. Total distance to pass platform = 100 + 260 = 360 meters. Time taken = 360 / 20 = 18 seconds.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Time Speed and Distance Questions

Question #1
A local train spans a track sector in 40 minutes. If its speed is lowered by 6 km/h, it tracks the same sector in 45 minutes. Find the distance of this track sector.
A. 40 km
B. 36 km
C. 32 km
D. 44 km

Correct Answer: Option B


Explanation:
Let original speed be s. s * (40/60) = (s - 6) * (45/60) => 40s = 45s - 270 => 5s = 270 => s = 54 km/h. Distance = 54 * (40/60) = 36 km.

This question belongs to: Maths Time Speed and Distance
Question #2
A train passes a 110-meter long bridge in 12 seconds and a standard sign post in 7 seconds. Find the length of the train.
A. 175 meters
B. 154 meters
C. 140 meters
D. 160 meters

Correct Answer: Option B


Explanation:
Time taken to cross the bridge alone = 12 - 7 = 5 seconds. Speed of train = 110 / 5 = 22 m/s. Length of train = Speed * Time to cross sign post = 22 * 7 = 154 meters.

This question belongs to: Maths Time Speed and Distance
Question #3
A person rows 24 km downstream in 3 hours and covers the same distance upstream in 6 hours. What is the speed of the boat in still water.
A. 8 km/h
B. 6 km/h
C. 5 km/h
D. 7 km/h

Correct Answer: Option B


Explanation:
Downstream speed = 24 / 3 = 8 km/h. Upstream speed = 24 / 6 = 4 km/h. Speed in still water = (8 + 4) / 2 = 6 km/h.

This question belongs to: Maths Time Speed and Distance