A train 140 meters long passes a stationary observer in 7 seconds. How long will it take to cross a platform 260 meters long? MCQ with Answer and Explanation

A train 140 meters long passes a stationary observer in 7 seconds. How long will it take to cross a platform 260 meters long?
A. 22 seconds
B. 18 seconds
C. 24 seconds
D. 20 seconds
Answer: Option D
Solution (By JKSSB Mock Tests)
Speed of train = 140 / 7 = 20 m/s. Total distance to pass platform = 140 + 260 = 400 meters. Time required = 400 / 20 = 20 seconds.

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Practice More Time Speed and Distance Questions

Question #1
A person walks from his house to his office at a speed of 4 km/h and reaches 10 minutes late. If he walks at 5 km/h, he reaches 5 minutes early. Find the distance between his house and office.
A. 6 km
B. 4 km
C. 5 km
D. 8 km

Correct Answer: Option C


Explanation:
Time difference = 10 - (-5) = 15 minutes = 1/4 hour. Let distance be d. d/4 - d/5 = 1/4 => d/20 = 1/4 => d = 5 km.

This question belongs to: Maths Time Speed and Distance
Question #2
A train running at 90 km/h crosses a platform double its length in 36 seconds. What is the length of the platform?
A. 750 meters
B. 600 meters
C. 500 meters
D. 400 meters

Correct Answer: Option B


Explanation:
Speed of train = 90 * (5/18) = 25 m/s. Total distance covered in 36 seconds = 25 * 36 = 900 meters. Let train length be L, so platform length = 2L. L + 2L = 900 => 3L = 900 => L = 300 meters. Platform length = 2L = 600 meters.

This question belongs to: Maths Time Speed and Distance
Question #3
A car runs at 50 km/h for 3 hours and then tracks at 70 km/h for the next 2 hours. Find the average speed across the whole route.
A. 56 km/h
B. 58 km/h
C. 60 km/h
D. 62 km/h

Correct Answer: Option B


Explanation:
Distance 1 = 50 * 3 = 150 km. Distance 2 = 70 * 2 = 140 km. Total distance = 290 km. Total time = 5 hours. Average speed = 290 / 5 = 58 km/h.

This question belongs to: Maths Time Speed and Distance